Last updated at April 19, 2021 by Teachoo

Transcript

Example 25 If the radius of a sphere is measured as 9 cm with an error of 0.03 cm, then find the approximate error in calculating its volume.Given Radius of sphere = r = 9 cm Error in radius = โr = 0.03 cm We need to find Error in calculating Volume Let Volume of sphere = V = ๐/๐ ๐ ๐^๐ โด We need to find โV Now, โV = ๐๐/๐๐ โr = ๐(4/3 ๐๐^3 )/๐๐ โr = 4/3 ๐ (๐๐^3)/๐๐ โr = 4/3 ๐ (3๐^2 )(0.03 ) = 4๐๐^2(0.03) = 4๐(9)2 (0.03) = 9.72๐ cm3 Hence, approximate error in calculating volume is 9.72๐ cm3

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.